Find the dimensions of the rectangular field.

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To find the dimensions of a rectangular field with a perimeter of 60 meters and an area of 200 square meters, the equations for perimeter (p = 2a + 2b) and area (A = ab) are used. By substituting the perimeter equation into the area equation, one can express one variable in terms of the other. Solving these equations simultaneously will yield the lengths of the sides a and b. Drawing a diagram can aid in visualizing the problem. The solution will provide the specific dimensions of the field.
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Help Me Please!

I need help with this problem.

The perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions
 
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Please help me I beg you!
 
Show how you have tried to approach the problem.
 
I need somebody to show me how to do it.
 
Try not to be lazy.

The perimeter of a rectangle is p=2a+2b=60 meters, where a and b are contiguous sides' lengths. Do you see this? (Drawing a figure would be helpful.)

The area A=200 meters2. In terms of a and b the area is thus equal to...
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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