Find the displacement from the equilibrium position

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SUMMARY

The discussion focuses on calculating the displacement from the equilibrium position of a particle located at a distance of x=£/12 from a wave source at time t=T/4, with an amplitude A=0.2 m. The relevant wave equation is x=A*cos(wt), where the argument incorporates both time and distance. The correct displacement is determined to be £=0.24 m, derived from substituting the values into the wave equation. Participants emphasize the importance of understanding the full traveling wave equation, which includes both time and distance components.

PREREQUISITES
  • Understanding of wave mechanics and displacement concepts
  • Familiarity with trigonometric functions in wave equations
  • Knowledge of wave properties such as amplitude and wavelength
  • Basic grasp of the relationship between wave velocity, wavelength, and period (v=λ/T)
NEXT STEPS
  • Study the full traveling wave equation, including time and distance components
  • Explore the concept of wave velocity and its calculation
  • Research the relationship between amplitude and displacement in wave mechanics
  • Review resources on wave behavior, such as the Hyperphysics website
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, and anyone seeking to understand the mathematical modeling of wave behavior in various contexts.

zade70
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Homework Statement


Find the displacement from the equilibrium position of the particle that is in the distance x=£/12 from the wave source, for the moment t=T/4. The amplitude of the wave is A=0.2 m

Homework Equations


x=A*cos(wt)=A*cos2*pi/T* t

The Attempt at a Solution


x=£/12
£/12=0.02*cos2*3.14/T *T/4
£=0.02*12=0.24 m. Is this what I should find?
 
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You'll want to start with the full traveling wave equation which accounts for both time and distance from the source (the argument of the trig function for the wave has terms for both time and distance).
 
gneill said:
You'll want to start with the full traveling wave equation which accounts for both time and distance from the source (the argument of the trig function for the wave has terms for both time and distance).
Could you show me that equation. Maybe we haven't learned it yet.
 
gneill said:
You can look it up on the web. Search for "traveling wave". For example, look at the Hyperphysics website entry.
No we haven't done any equation with velocity except v= λ/T
 
zade70 said:
No we haven't done any equation with velocity except v= λ/T
That's the velocity that the wave travels from the source, and it is relevant here as part of the traveling wave equation. If you haven't covered it yet you'll have to read ahead in order to answer this question.
 

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