Find the electric potential energy

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SUMMARY

The discussion centers on calculating electric potential energy using the equations V = kq/r and U = Vq. The user correctly computes the electric potential (V) as -450 V and the electric potential energy (U) as 900 nJ. However, a clarification is provided regarding the form of the second equation used in the calculations. The calculations are confirmed to be accurate despite the notation issue.

PREREQUISITES
  • Understanding of Coulomb's Law and the constant k (Coulomb's constant)
  • Familiarity with electric potential (V) and electric potential energy (U)
  • Basic algebra for manipulating equations
  • Knowledge of units for electric charge (Coulombs) and energy (Joules)
NEXT STEPS
  • Review the derivation of Coulomb's Law and its applications
  • Study the relationship between electric potential and electric potential energy
  • Explore the concept of electric fields and their relation to potential
  • Practice solving problems involving electric potential energy in various configurations
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators looking for examples of electric potential calculations.

Fatima Hasan
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Homework Statement


viber_image.jpg


Homework Equations


##V= \frac {kq}{r}##
##V= \frac {U}{q}##

The Attempt at a Solution


##V= \frac {kq}{r}## = 9*109*-5*10-9 /0.1= -450 V
##U= \frac {V}{q}## = -450 * -2*10-9 = 900nJ
Is my answer correct ?
 

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Fatima Hasan said:

Homework Statement


View attachment 223345

Homework Equations


##V= \frac {kq}{r}##
##V= \frac {U}{q}##

The Attempt at a Solution


##V= \frac {kq}{r}## = 9*109*-5*10-9 /0.1= -450 V
##U= \frac {V}{q}## = -450 * -2*10-9 = 900nJ
Is my answer correct ?
Yes, but the form of your second relevant equation in your last line of calculations is not. Fortunately you did the actual calculation correctly anyways :smile:
 
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