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## Homework Statement

Find the equation of the tangent to the curve y=2cos^3x at x=pi/3

## Homework Equations

## The Attempt at a Solution

y=2cos^3x

dy/dx=-6sinxcos^2x

0=-6sinxcos^2x

set x = pi/3 and solve for the derivative, plug the answer into y=2cos^3x

where do I go from here?

Do I take that value of the slope and use the points found by pi/3 and use m=y2-y1/x2-x1?

Thanks