Find the center of a circle given a tangent line & point

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SUMMARY

The task is to find the center and radius of a circle that passes through point A(1,1) and is tangent to the line y=2x-3 at point B(3,3). The solution involves using the coordinates of the tangent point and the slope-intercept form of the tangent line. The discussion highlights the necessity of incorporating both points A(1,1) and B(3,3) to derive the correct center of the circle, as relying solely on the tangent point leads to an infinite number of circles. The correct approach requires simultaneous equations derived from the diameters formed by these points.

PREREQUISITES
  • Understanding of circle equations and their properties
  • Familiarity with tangent lines and their equations
  • Knowledge of simultaneous equations
  • Basic coordinate geometry concepts
NEXT STEPS
  • Study the derivation of circle equations from given points and tangents
  • Learn how to apply simultaneous equations to solve geometric problems
  • Explore the relationship between tangent lines and circles in coordinate geometry
  • Investigate the concept of diameters and their role in determining circle centers
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Students studying geometry, mathematics educators, and anyone interested in solving geometric problems involving circles and tangents.

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Homework Statement


"Find the center and radius of the circle that passes through A(1,1) and is tangent to the line y=2x-3 at the point B(3,3). (Picture of the graph: https://imgur.com/a/0wAnqcU)

Homework Equations


Here's a link: https://imgur.com/a/y71Z9GY

The Attempt at a Solution


Soo, I've been tryiing to use the equation shown in the link above, but i get an answer that i don't quite get. In the website where i found this (https://math.stackexchange.com/ques...ntre-of-circle-with-equation-of-tangent-given) it told me to use the coordinates where the tangent touches the circle.

I used the points (3,3) and substitute it with the x0 and the y0, and substitute the m and c with 2 and 3 respectively. When i simplify the equation, i get 15/3 for both x and y points, which will result to another (3,3). I might've missed something but the resulted coordinates isn't the center of the given circle.
 
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your c is -3

And I don't think that's the formula you need: That formula only consists of the point where the circle touches the tangent and the linear equation. What about A(1,1)? Although I can't fully understand the formula, but just knowing the tangent point and equation won't be enough to make a circle(you can actually but you will make a infinite amount of them since A(1,1) doesn't matters), you need to find a formula that somehow takes the A(1,1) into a count.
 
Last edited:
You can get equations for 2 diameters out of the given information. Then solve simultaneously for the centre.
 
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