MHB Find the factors using a complete square

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The expression $x^2 + 2ax + a^2$ can be rewritten as the complete square $(a + x)^2$. To find the factors of $x^2 + 2ax + a^2 - 9$, it can be expressed as $(a + x)^2 - 9$. This further simplifies to the difference of squares, resulting in the factors $(a + x - 3)(a + x + 3). The discussion emphasizes the application of completing the square and factoring techniques. Understanding these methods is crucial for solving quadratic expressions effectively.
mathlearn
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Problem

First you are asked to,

write this expression as a complete square $x^2+2ax+a^2$

& ii. Using that find the factors of $x^2+2ax+a^2-9$

Workings

i $(a + x)^2$

Where do I need help

ii. Using that find the factors of $x^2+2ax+a^2-9$

Many Thanks :)
 
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mathlearn said:
Problem

First you are asked to,

write this expression as a complete square $x^2+2ax+a^2$

& ii. Using that find the factors of $x^2+2ax+a^2-9$

Workings

i $(a + x)^2$

Where do I need help

ii. Using that find the factors of $x^2+2ax+a^2-9$

Many Thanks :)

You want to factorize $(a+x)^2-9$. But this is same as $(a+x)^2-3^2=(a+x-3)(a+x+3)$.
 
caffeinemachine said:
You want to factorize $(a+x)^2-9$. But this is same as $(a+x)^2-3^2=(a+x-3)(a+x+3)$.

Thank you very much caffeinemachine :)
 

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