Find the instantanous velocity

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Homework Help Overview

The discussion revolves around finding the instantaneous velocity at a specific time using the function h(t) = 16 + 24t - 16t². The original poster expresses confusion regarding the manipulation of the term h(1 + Δt) in the context of the velocity formula.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct formulation of h(1 + Δt) and its implications for calculating instantaneous velocity. There are attempts to clarify how to expand the expression and concerns about the accuracy of the resulting terms.

Discussion Status

Some participants have provided hints and guidance on how to approach the problem, particularly in expanding the h(1 + Δt) term. There is ongoing clarification regarding the inclusion of all relevant terms in the equation, and multiple interpretations of the problem setup are being explored.

Contextual Notes

Participants note the importance of considering the limit as Δt approaches 0 in the context of instantaneous velocity. There is also a mention of a related question in another section of the forum, suggesting a potential overlap in discussions.

[Nicolette]
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1. Homework Statement

Find the instantaneous velocity at t=1 by computing v(1)= [h(1+LaTeX Code: \\Delta t)-h(1)]/LaTeX Code: \\Delta t

I found that v(1)= -8ft/sec. Also I know h(1)=24 but i don't understand how to manipulate the h(1+LaTeX Code: \\Delta t) to get the solution.


2. Homework Equations

h(t)=16+24t-16t2


3. The Attempt at a Solution

The solution the teacher gave is v(1)=-8-16tLaTeX Code: \\Delta
 
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Write out \frac{h(1+\Delta t)-h(1)}{\Delta t}. The part you have a problem with is probably the h(1+\Delta t) term I will give you a hint. h(1+\Delta t)=16+24(1+\Delta t)+... fill in the rest and work out the brackets.

Note that for an instant of time \Delta t \rightarrow 0 so your final answer is correct.
 
Last edited:
How did you get that h(1+t)=16+24(1+t)?

and when i fill in the rest i get 16+24(1+t)-24 which when worked out would be 16+24t and is not right

:confused:
 
Don't overlook the dots. h(1+\Delta t)=16+24(1+\Delta t)+... my intention was for you to fill in the dots, so basically add the quadratic term to it as well. I hope this is sufficiently clear if not just ask again!

Edit: I just noticed that the same question was asked in the correct introductory physics section. Perhaps a mod could merge this thread with https://www.physicsforums.com/showthread.php?t=305889.
 

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