Find the Launch Speed for a 20m High Projectile

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Homework Help Overview

The problem involves determining the launch speed of a projectile that reaches a maximum height of 20 meters, with a specified direction of velocity 1 second after launch.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply kinematic equations to find the launch speed but questions whether sufficient information is provided to solve the problem.

Discussion Status

Some participants engage by welcoming the original poster and suggesting a focus on finding the vertical component of the initial velocity. There is a mix of attempts and encouragement, but no explicit consensus on the solution process is reached.

Contextual Notes

The original poster expresses uncertainty about the adequacy of the information provided for solving the problem, indicating a potential gap in understanding the relationships between the variables involved.

voygehr
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Homework Statement


The maximum height reached by a projectile is 20 m. The direction of the velocity 1.0 s after launch is 20°. Find the speed of launch.


Homework Equations


vertical component of velocity = [tex]u \sin\theta - gt[/tex]
horizontal component of velocity = [tex]u\cos\theta[/tex]
where theta is the launch angle


The Attempt at a Solution


I made several attempts to solve this but I can't seem to figure it out. Are we presented with enough information?
 
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welcome to pf!

hi voygehr! welcome to pf!

(have a theta: θ :wink:)

find vy0 first …

show us what you get :smile:​
 
just solved it!

v=34 m/s at 36°

thanks anyway! (do I delete this thread now?)
 
no, it remains for ever as a triumph of human perseverance and ingenuity! :biggrin:
 
haha excellent!
 

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