Find the length of Robin's route

[chwala]

Homework Statement

Find the length of Robin's route. (See attached)

Relevant Equations

network models

I am self-studying this. My interest is on part b. Part A i found that to be easy.

Firstly, i note that nodes $A$ and $J$ are odd. Suggesting an Eulerian circuit. I also need to read about this chinese postman approach. If i can be directed on the key difference, then that's also fine.

Therefore we have the these paths to consider the pairing involving $ACEJ$ ,Robin starts at C and ends at E. Therefore, the possible combinations are $3;[ AC + EJ, AE + CJ, AJ + CE]$.

From these three the shortest one is $AC + EJ = (13+8) + (6+2+23)=52$miles.

The other two will each give $82$ miles. Therefore, the length of Robin's route is $315 + 52= 367$ miles. I also need to understand what they mean by total weight of network, but as far as the math-related part is concerned, I am conversant!

Blessings!!

 

[.Scott]

The purpose of the assignment is to use the algorithm. Not to find the answer with your own methods.
"Weight" refers to the attribute of a path that is to be minimized. So, it this case, it is the lengths.

 

[chwala]

The purpose of the assignment is to use the algorithm. Not to find the answer with your own methods.
"Weight" refers to the attribute of a path that is to be minimized. So, it this case, it is the lengths.

@Scott A, I found the algorithm bit understandable as well. It's not difficult; I just posted the highlights, specifically the reasoning behind the question. If you have more insights, that's what I'm looking for, prompting this post.

 

[.Scott]

Are you writing code? If so, which language?

 

[chwala]

Are you writing code? If so, which language?

I meant on the nodes, I did not write a code, you could enlighten me on that.

 

[.Scott]

The wiki article on Dijkstr's algorithm uses pseudo code, but if you coded it using Python, JavaScript, C, etc., your computer come up with an answer.

 

[chwala]

The wiki article on Dijkstr's algorithm uses pseudo code, but if you coded it using Python, JavaScript, C, etc., your computer come up with an answer.

This question from a Decision Maths paper raises doubts about whether students are required to use coding.

 

[pbuk]

Firstly, i note that nodes $A$ and $J$ are odd. Suggesting an Eulerian circuit.

Can an Eulerian circuit exist in a network with odd nodes?

I also need to read about this chinese postman approach. If i can be directed on the key difference, then that's also fine.

The term "Chinese postman problem" refers to a problem like this where an Eulerian circuit does not exist. The approach to solving it is to add paths (of minimal length) to create an Eulerian circuit, which is what you have done.

I also need to understand what they mean by total weight of network

This is the figure 315 you have used.

 

[WWGD]

Homework Statement: Find the length of Robin's route. (See attached)
Relevant Equations: network models

View attachment 359195

I am self-studying this. My interest is on part b. Part A i found that to be easy.

Firstly, i note that nodes $A$ and $J$ are odd. Suggesting an Eulerian circuit. I also need to read about this chinese postman approach. If i can be directed on the key difference, then that's also fine.

Therefore we have the these paths to consider the pairing involving $ACEJ$ ,Robin starts at C and ends at E. Therefore, the possible combinations are $3;[ AC + EJ, AE + CJ, AJ + CE]$.

From these three the shortest one is $AC + EJ = (13+8) + (6+2+23)=52$miles.

The other two will each give $82$ miles. Therefore, the length of Robin's route is $315 + 52= 367$ miles. I also need to understand what they mean by total weight of network, but as far as the math-related part is concerned, I am conversant!

Blessings!!

Total weight of an undirected network is the sum of the weights on all edges. It may differ for directed networks.