chwala
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- Homework Statement
- Find the length of Robin's route. (See attached)
- Relevant Equations
- network models
I am self-studying this. My interest is on part b. Part A i found that to be easy.
Firstly, i note that nodes ##A## and ##J## are odd. Suggesting an Eulerian circuit. I also need to read about this chinese postman approach. If i can be directed on the key difference, then that's also fine.
Therefore we have the these paths to consider the pairing involving ##ACEJ## ,Robin starts at C and ends at E. Therefore, the possible combinations are ##3;[ AC + EJ, AE + CJ, AJ + CE]##.
From these three the shortest one is ##AC + EJ = (13+8) + (6+2+23)=52##miles.
The other two will each give ##82## miles. Therefore, the length of Robin's route is ##315 + 52= 367## miles. I also need to understand what they mean by total weight of network, but as far as the math-related part is concerned, I am conversant!
Blessings!!
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