hi i have a photo with some given information. I need to find the length of all three sides of that triangle and also the area of the triangle
I have already found them but i get 2 different results
I have used both cosinus and pythagoras
The Attempt at a Solution
I already got that length of AC is 20 since thats one of the given lengths. CB i got to be 42,1 and AB i sometimes get to be 19,2 when i use cosiunus, but when i use pythagoras and devide the triangle into 3 parts i get the length of AB to be 31 which is correct?
and my area is 0,5*hight*b where the hight is 3*the length of MD. so i got MD to be 9,89 and therefore my area is 0,5*29,67*20 = 296 but it just seems too big?
can anyone please check my attachment and help me out?