Find the magniture of the vector using the figure below

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SUMMARY

The discussion focuses on calculating the magnitude of a vector resulting from the sum of three vectors, specifically addressing the components Ax, Bx, Ay, Cx, and Cy. The user initially miscalculated Cx and Cy due to confusion regarding the angle measurements. Correct calculations involve using Cx = -12Cos(25) and Cy = 12sin(25), with adjustments for angle orientation. The final magnitude is determined using the formula √(Ax + Bx + Cx)² + (Ay + By + Cy)².

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Homework Statement



Find the magnitude of the vector that is the sum of the three vectors , , and in the figure : figure is the link
http://imageshack.us/photo/my-images/14/yf0134.jpg/




Homework Equations





The Attempt at a Solution



What I did was obtain Ax=0 Bx=7.5

Ay=-8.00 and B13

My problem came when trying to get Cx and Cy.

The way the vector is placed in the figure confuses me but I got Cy= 12sin(25)= -10.87 since it is on the negative side, and Cx= 12Cos25=-5.07.

I then got the squareroot of Ax+Bx+Cx^2+Ay+By+Cy^2
Did I create the triangle wrong? If so how can I make sure to not make this same mistake
 
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That looks OK to me...
Haven't you got Cx and Cy the wrong way around though?
After all C is longer in x than it is in y and you have Cy as the bigger.

just a niggle, Cx is not 12Cos25
... you should have written Cx = -12Cos25 because that is what it is.
(you can lose marks that way)

You are used to the angle measured wrt the x-axis ... in which case Cx=12Cos(205), which is the same.
 
Thank you!
 
No worries - you see all the other angles were wrt the y axis? so that angle in C was 115 degrees anticlockwise from the y axis. Then you can use the same formula you used for the others.

You can always construct the kinds of angles that make the math easier for you.
 

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