Find the magniture of the vector using the figure below

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Homework Help Overview

The problem involves finding the magnitude of a vector that is the sum of three vectors, as depicted in a provided figure. The context is within vector addition and trigonometry.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the components of the vectors but expresses confusion regarding the placement of vector C in the figure. They raise a question about the correctness of their calculations for Cx and Cy.

Discussion Status

Some participants provide feedback on the original poster's calculations, suggesting potential errors in the signs of the components and the angles used. There is an exchange of ideas regarding the interpretation of angles in relation to the axes, indicating a collaborative exploration of the problem.

Contextual Notes

Participants note that the angles for vector C are measured differently than those for the other vectors, which may contribute to the confusion. There is an emphasis on ensuring clarity in the angle measurements to avoid mistakes in calculations.

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Homework Statement



Find the magnitude of the vector that is the sum of the three vectors , , and in the figure : figure is the link
http://imageshack.us/photo/my-images/14/yf0134.jpg/




Homework Equations





The Attempt at a Solution



What I did was obtain Ax=0 Bx=7.5

Ay=-8.00 and B13

My problem came when trying to get Cx and Cy.

The way the vector is placed in the figure confuses me but I got Cy= 12sin(25)= -10.87 since it is on the negative side, and Cx= 12Cos25=-5.07.

I then got the squareroot of Ax+Bx+Cx^2+Ay+By+Cy^2
Did I create the triangle wrong? If so how can I make sure to not make this same mistake
 
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That looks OK to me...
Haven't you got Cx and Cy the wrong way around though?
After all C is longer in x than it is in y and you have Cy as the bigger.

just a niggle, Cx is not 12Cos25
... you should have written Cx = -12Cos25 because that is what it is.
(you can lose marks that way)

You are used to the angle measured wrt the x-axis ... in which case Cx=12Cos(205), which is the same.
 
Thank you!
 
No worries - you see all the other angles were wrt the y axis? so that angle in C was 115 degrees anticlockwise from the y axis. Then you can use the same formula you used for the others.

You can always construct the kinds of angles that make the math easier for you.
 

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