Find the mass of object knowing the applied force and coefficient of friction

AI Thread Summary
To find the mass of an object given a force of 45 Newtons and a coefficient of friction of 0.26, the frictional force can be equated to the applied force since it is just enough to overcome friction. The equation for frictional force is frictional force = coefficient of friction x weight. By substituting the known values into the equation, 45 = 0.26m(9.8), the mass can be calculated as m = 17.65 kg. This approach clarifies that the applied force equals the frictional force, allowing for the determination of mass. Understanding this relationship is crucial for solving similar physics problems.
liz777
Messages
19
Reaction score
0

Homework Statement



If a force of 45 Newtons is needed to overcome friction and the coefficient of friction=0.26, what is the mass of the object?

The Attempt at a Solution



So would I need to find the frictional force first? But then I can't use the equation: (frictional force=coefficient of friction x weight) since I don't have the mass. I also thought about using the equation F=MA but then I don't have the acceleration, the friction, or the net force! Any help, I'm really stuck?
 
Physics news on Phys.org
liz777 said:
So would I need to find the frictional force first?
They give you the friction force. The way to interpret the given information is that the 45 N force is just enough to overcome friction, thus that force equals the friction.
But then I can't use the equation: (frictional force=coefficient of friction x weight) since I don't have the mass.
Sure you can use that equation. Remember that you're asked to find the mass.
 
Ok, so what you're saying is that the applied force equals the friction, in this case. I thought it wouldn't move though if that was true? I'm just confused on this concept.

But anyway, using that information, frictional force=coefficient of friction x weight
45=0.26m(9.8)
45=2.55m
m=17.65kg
Is that right?
 
Yes.
You are given two values, and you need to solve for one of them using an equation with four variables, three of which are known (the other being g).
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top