Find the Mass of Sun if given are T and d?

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Homework Help Overview

The original poster is investigating the mass of the Sun using the orbital characteristics of the Earth, specifically the time it takes for the Earth to orbit the Sun and the distance between them. The problem involves gravitational force and centripetal acceleration concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between gravitational force and centripetal acceleration, questioning why these two concepts can be considered equal in the context of Earth's orbit. There is an exploration of the formulas involved and their implications for calculating the mass of the Sun.

Discussion Status

Some participants have provided clarifications regarding the distinction between force and acceleration, while others have suggested starting with calculations related to centripetal acceleration. The discussion is ongoing, with various interpretations being explored.

Contextual Notes

There are mentions of literature that discusses the relationship between centripetal force and gravitational force, as well as the assumption of a circular orbit for the Earth, despite its slight elliptical nature.

arddi2007
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Homework Statement


Knowing that the Earth spins around the Sun for 365 days and the distance Earth->Sun is 1.5x10^11 m, what's the mass of the Sun?


Homework Equations



F=G Me x Ms/distance^2

where Me - Mass of Earth, and Ms - Mass of Sun

In some literature, I noticed that for similar problems was used the formula for centripetal acceleration, although I'm not sure why:

acp = v^2/r=(2 x PI x r/T)^2 / r

where r - radius of Earth, and T - time for the Earth to spin around Sun (?).




The Attempt at a Solution



You can notice those two formulas. The literature I found this equation in says that F and acp are equal, but it doesn't explain why. If that's the case, then the equation will be a piece of cake. But I need to know why F (pulling force between Earth and Sun) and acp are equal (if that's correct).

THANK YOU FOR ANY HELP AT ALL!
 
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arddi2007 said:
You can notice those two formulas. The literature I found this equation in says that F and acp are equal, but it doesn't explain why. If that's the case, then the equation will be a piece of cake. But I need to know why F (pulling force between Earth and Sun) and acp are equal (if that's correct).

They are not equal, and for a very good reason: one is a force and the other is an acceleration. They are different things.

However! They can be closely related through Newton's second law if the acceleration in question is the result of the force in question acting upon a given mass. In this case, that mass is the Earth.

You know that gravitational force is holding the Earth in its orbit around he Sun. This force provides the centripetal acceleration of the Earth in its orbit. Can you find an expression for the gravitational acceleration of the Earth by the Sun?
 
Now that I've checked the literature again, it says that the centripetal force of Earth (Fcp=mv^2 / distance) is equal to the force which Earth and Sun pull each other.

Now, my question is, is that correct? If it is, why are they equal?
 
arddi2007 said:
Now that I've checked the literature again, it says that the centripetal force of Earth (Fcp=mv^2 / distance) is equal to the force which Earth and Sun pull each other.

Now, my question is, is that correct? If it is, why are they equal?

That is correct, assuming a circular orbit for the Earth.

In reality, Earth's orbit is not perfectly circular but very slightly elliptical. So there are small variations in the distance between the Earth and Sun over the course of a year that affects the gravitational force between them. The velocity of the Earth in its orbit also varies slightly over the year as it follows the ellipse. But none of this is going to affect what it is you want to do here.

Why not start by calculating a number for the centripetal acceleration?
 

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