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**1. Homework Statement**

A block of mass 2.0kg is dropped from height h=70cm onto a spring of spring constant k=1960 N/m. Find the maximum distance the spring is compressed.

**2. Homework Equations**

KE initial + PE initial = KE final + PE final

KE = 1/2(mass)(velocity)^2

PE = mgh or, when dealing with a spring, PE = 1/2 (k)(compression distance)^2

**3. The Attempt at a Solution**

The initial velocity is zero, so the initial KE is zero

The final height is zero so the final PE is zero

2kg(9.8)(.7m) = (1/2)(1960)x^2

where x is the distance the spring is compressed

solve for x.... x = .118m

but it is not the right answer....

Any help is appreciated,

Thanks,

A