Find the mean, variance, and standard deviation

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SUMMARY

The discussion focuses on calculating the mean, variance, and standard deviation for a scenario involving four children in a family, specifically finding the probability of having exactly three girls. The correct probability for a girl being born is 0.50, not 0.75 as initially assumed. Using the binomial distribution method, the mean is calculated as np, variance as npq, and standard deviation as the square root of variance. The correct calculations yield a mean of 2, variance of 1.5, and standard deviation of approximately 1.22.

PREREQUISITES
  • Understanding of binomial distribution equations
  • Knowledge of probability concepts, specifically independent events
  • Familiarity with statistical measures: mean, variance, and standard deviation
  • Ability to apply combinatorial principles in probability
NEXT STEPS
  • Study the binomial distribution formula in detail, focusing on p(x) = C(n, k) p^k (1-p)^{n-k}
  • Explore the concept of independent events in probability theory
  • Learn how to derive mean, variance, and standard deviation from probability distributions
  • Practice problems involving combinatorial probability and statistical measures
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Students studying statistics, educators teaching probability concepts, and anyone looking to deepen their understanding of binomial distributions and statistical measures.

KatieLynn
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Homework Statement



If there are 4 children in a family, find the probability of getting exactly 3 girls. Find the mean, variance, and standard deviation. Use two different methods(binomial distribution method and general probability distribution method).

Homework Equations



Binomial distribution equations:
Mean=np
variance=npq
standard deviation= sq. root of variance

The Attempt at a Solution



mean= (4)(.75)=3

variance=(4)(.75)(.25)=.75

s.d.= .866

is that right?
 
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Not quite - this is a guess, but you are using the value of [tex]0.75[/tex] as p because out of the four children, three are girls? If so, that's not correct.

With the information you are given you can only assume that
  1. Births of boys and girls are independent
  2. The probability a boy is born is [tex]0.50[/tex] and the probability a girl is born is [tex]0.50[/tex]

Your method of calculation to find the mean, variance, and standard deviation are correct, but the value of [tex]p[/tex] isn't (as pointed out above)

You can use the formula

[tex] p(x) = C(4,x) p^x (1-p)^{4-x}[/tex]

to find the probability of exactly three girls with the binomial distribution.

For the "fundamental principles" piece: write down all possible ways for there to be four children, and use basic principles of equally likely outcomes.
 

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