Find the moment of inertia of a hoop

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SUMMARY

The moment of inertia of a hoop (thin-walled, hollow ring) with mass M and radius R about an axis perpendicular to the hoop's plane at an edge is calculated using the formula I = n * M * R^2, where n is the inertial constant. The axis of rotation must be positioned at the edge of the ring, not through the center. This adjustment is crucial for accurately determining the moment of inertia in this scenario.

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with rotational dynamics
  • Knowledge of the properties of a hoop or ring
  • Basic algebra for manipulating formulas
NEXT STEPS
  • Study the derivation of the moment of inertia for various shapes
  • Learn about the parallel axis theorem in rotational dynamics
  • Explore applications of moment of inertia in engineering problems
  • Investigate the differences between solid and hollow objects in terms of inertia
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Physics students, mechanical engineers, and anyone studying rotational motion and dynamics will benefit from this discussion.

trajan22
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Find the moment of inertia of a hoop (a thin-walled, hollow ring) with mass M and radius R about an axis perpendicular to the hoop's plane at an edge.

I know that I=n*m*r^2
where n is the inertial constant

but i think my main problem with this is where the axis of rotation is, I am thinking that it is through the center of the ring but can't be sure any help would be great.
 
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Suppose the ring is lying horizontally flat, and a vertical axis is passing through the centre of the ring. Now bodily move the axis in a horizontal direction, so that the axis is now passing through the edge, or circumference, of the ring. This new position for the axis shows you the intended axis of rotation for your problem.
 

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