Find the particular solution to Dy/Dx = 3x^2 + 1

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SUMMARY

The discussion focuses on finding the particular solution to the differential equation Dy/Dx = 3x^2 + 1 with the initial condition y(0) = 3. The user seeks guidance on solving this non-separable differential equation. The solution involves integrating both sides after rewriting the equation as dy = (3x^2 + 1)dx, leading to the integral ∫dy = ∫(3x^2 + 1)dx. The integration yields y = x^3 + x + C, where C is determined using the initial condition.

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Find the particular solution to Dy/Dx = 3x^2 + 1 when y(0) = 3

I've looked everywhere for steps to solve this problem, and every website I have been to has taught me how to do a question like this when each side has a Y (is separable) but I can't find out how to do one like the question above.

I don't need it to be done for me, I just would love to know the steps I should take in solving it.

Thanks!
 
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Starting from: $$\frac{dy}{dx} = f(x)$$ ... multiply both sides by ##dx##: $$dy = f(x)dx$$ ... integrate both sides: $$\int dy = \int f(x)dx$$

Although - Dy/Dx may not mean dy/dx in this case.
 
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