Find the pebble's position, velocity, and acceleration

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SUMMARY

The discussion focuses on determining the position, velocity, and acceleration of a pebble lodged in a tire rolling without slipping at a constant speed V. The velocity is expressed as v = V \hat{r} + Vt \omega \hat{\theta}, while the acceleration is given by a = -Vt \omega^{2} \hat{r} + 2V \omega \hat{\theta}. To find the position as a function of time, integration of the velocity is necessary, and Cartesian coordinates should be utilized through the transformations x = r cos(θ) and y = r sin(θ).

PREREQUISITES
  • Understanding of rotational motion and angular velocity
  • Familiarity with vector calculus and coordinate transformations
  • Knowledge of integration techniques for functions of time
  • Basic principles of kinematics in two dimensions
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  • Learn about vector calculus, specifically in polar and Cartesian coordinates
  • Practice integrating velocity functions to derive position and acceleration
  • Explore examples of rolling motion and the effects of slipping versus non-slipping conditions
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A tire rolls in a straight line without slipping. Its center moves with constant speed V. A small pebble lodged in the read of the tire touches the road at t = 0. Find the pebble's position, velocity, and acceleration as functions of time.

So \bold{v} = \dot{r} \bold{\hat{r}} + r \theta \bold{\hat{\theta}}.

Would it just be \bold{v} = V \bold{\hat{r}} + Vt \omega \bold{\hat{\theta}} and \bold{a} = -Vt \omega^{2} \bold{\hat{r}} + 2V \omega \bold{\hat{\theta}}?

Then to find the position as a function of time, integrate the velocity?

Thanks
 
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You need to do this in cartesian coords, because the center keeps moving.
 
So use the transformations x = r \cos \theta, y = r \sin \theta?
 
I had to do a problem similar to this, and I still don't understand it...
 

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