Find the pebble's position, velocity, and acceleration

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Homework Help Overview

The problem involves a tire rolling in a straight line with a pebble lodged in it, requiring the determination of the pebble's position, velocity, and acceleration as functions of time. The context is rooted in kinematics and rotational motion.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to express the velocity and acceleration of the pebble using vector notation and considers integration to find position. Some participants suggest using Cartesian coordinates due to the motion of the tire's center, while others propose transformations to express the position in terms of x and y coordinates.

Discussion Status

The discussion is ongoing, with participants exploring different coordinate systems and transformations. There is acknowledgment of confusion regarding the problem, indicating that further clarification may be needed.

Contextual Notes

There is a mention of a similar problem that caused confusion for one participant, suggesting that the original poster and others may be grappling with the complexities of the scenario.

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A tire rolls in a straight line without slipping. Its center moves with constant speed [tex]V[/tex]. A small pebble lodged in the read of the tire touches the road at [tex]t = 0[/tex]. Find the pebble's position, velocity, and acceleration as functions of time.

So [tex]\bold{v} = \dot{r} \bold{\hat{r}} + r \theta \bold{\hat{\theta}}[/tex].

Would it just be [tex]\bold{v} = V \bold{\hat{r}} + Vt \omega \bold{\hat{\theta}}[/tex] and [tex]\bold{a} = -Vt \omega^{2} \bold{\hat{r}} + 2V \omega \bold{\hat{\theta}}[/tex]?

Then to find the position as a function of time, integrate the velocity?

Thanks
 
Last edited:
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You need to do this in cartesian coords, because the center keeps moving.
 
So use the transformations [tex]x = r \cos \theta[/tex], [tex]y = r \sin \theta[/tex]?
 
I had to do a problem similar to this, and I still don't understand it...
 

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