Find the power series in x for the general solution of (1+2x^2)y"+7xy'+2y=0

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SUMMARY

The discussion centers on finding the power series solution for the differential equation (1+2x^2)y'' + 7xy' + 2y = 0. The correct recurrence relation identified is a_{2n} = -\frac{2n+1}{n+1}a_n. The user attempts to derive the general solution using the recurrence relations for even and odd terms but struggles to match the book's answer. The conversation highlights the need for clarity in separating terms and solving the recurrence relations effectively.

PREREQUISITES
  • Understanding of power series and their convergence
  • Familiarity with differential equations, specifically second-order linear equations
  • Knowledge of recurrence relations and their solutions
  • Basic calculus, including differentiation and series manipulation
NEXT STEPS
  • Study the method of solving second-order linear differential equations using power series
  • Learn about recurrence relations and their applications in series solutions
  • Explore the concept of generating functions for sequences
  • Review examples of power series solutions in textbooks or online resources
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Students and educators in mathematics, particularly those focusing on differential equations and series solutions, as well as anyone seeking to deepen their understanding of recurrence relations in mathematical analysis.

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Homework Statement


Find the power series in x for the general solution of (1+2x^2)y"+7xy'+2y=0.

Homework Equations


None.

The Attempt at a Solution


I'll post my whole work.
 
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This is my work, I have more to post.
 

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This work comes first, the above one comes after this one.
 

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But I don't know how to get to the book's answer.
 

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You have the correct recurrence relation a_{2n} = - \frac{2n+1}{n+1}a_n. You just haven't tried to solve it.

Recurrences of the form <br /> a_{n+1} = f(n)a_n have the solution <br /> a_n = a_0\prod_{k=0}^{n-1} f(k) where by convention <br /> \prod_{k=0}^{-1} f(k) = 1.
Recurrences of the form <br /> a_{n+2} = f(n)a_n can be turned into the above form by treating even and odd terms separately: First set n = 2m and b_m = a_{2m} to obtain <br /> b_{m+1} = f(2m)b_m and then set n = 2m+1 and c_m = a_{2m+1} to obtain <br /> c_{m+1} = f(2m+1)c_m.
 
But that's not the answer in the book. How do I get the answer in the book?
 
Are you saying that <br /> y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{m=0}^\infty b_mx^{2m} + \sum_{m=0}^\infty c_mx^{2m+1} with b_m and c_m obtained as I have suggested is not the answer in the book?

What do you get for b_m and c_m?
 

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