Find the Probability: P(X<1/2 | Y=1)

[kingwinner]

Homework Statement

Suppose X and Y are jointly continuous random variables with joint density function
f(x,y)=6x²y, 0<x<y, x+y<2
f(x,y)=0, otherwise
Find P(X<1/2 | Y=1).

Homework Equations

The Attempt at a Solution

By definition,
P(X<1/2 | Y=1)
1/2
=∫ f_X|Y(x|y=1) dx
-∞

My computations:
Marginal density of Y:
fY(y)=2y^4, 0<y<1
fY(y)=2y(2-y)^3, 1<y<2


Condition density of X given Y=y:
Case 1: For given/fixed 0<y<1,
f_X|Y(x|y)=3x^2 / y^3, 0<x<y

Case 2: For given/fixed 1<y<2,
f_X|Y(x|y)=3x^2 / (2-y)^3, 0<x<2-y

I hope these are correct. Now P(X<1/2 | Y=1) is the troublesome case because we are given Y=1, which formula for f_X|Y(x|y) should I use?


Thanks for any help!

 

[Avodyne]

Your two formulas are the same at y=1, so it doesn't matter which one you use!

 

[kingwinner]

OK, but in general will they always be the same? What should we do in such a case in general?

 

[Avodyne]

If correctly derived from a given joint density function, yes, they must be the same.

 

[kingwinner]

um...Any proof about it?