Find The Range And Inverse (please Help I Have Test Monday)

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SUMMARY

The discussion focuses on finding the range and inverse of the function f(x) = √[(8x² + 1) / (9 - 5x²)]. The range can be determined by ensuring the radicand is non-negative, which leads to specific restrictions on y. The inverse function is found by swapping x and y in the equation, although solving for y in terms of x may not always be feasible with elementary functions. Understanding these concepts is crucial for accurately determining both the range and inverse of the given function.

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I don't understand this at all...

Find the Range and Inverse of f(x) = square root of [(8x^2 +1)/ (9-5x^2)]


I am so confused please help!
 
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The range of a function is all the values f(x) can take. The inverse of a function is basically the function that cancels it out. The inverse of division by 3 is multiplication by 3. The inverse of square rooting a positive number is squaring that number. To find the inverse function when you have a general [tex]y=f(x)[/tex] is to swap the y's and x's, ie [tex]x=f(y)[/tex], and it is not necessarily required to solve again for y, and in general it is not even possible in terms of elementary functions, but sometimes you lose marks when you can but you don't.
 
The range is easily solvable because only x^2 terms exist. Solving for x in terms of y can thus be done by a simple square root. Just make sure the radicand is not negative and that will give you the restrictions for the range y.
 

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