Find the rate of change of the current in the inductor

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SUMMARY

The discussion focuses on calculating the rate of change of current in an inductor when the battery current is 0.50 A. The relevant equation used is the induced electromotive force (emf) formula, L (dI/dt), where L is the inductance. The voltage across the inductor is determined to be 2 V, leading to a calculated rate of change of current, dI/dt, of 200 A/s. The participants clarify the relationship between the battery current and the inductor current, emphasizing the importance of understanding potential differences in the circuit.

PREREQUISITES
  • Understanding of inductors and their behavior in electrical circuits
  • Familiarity with the formula for induced emf: L (dI/dt)
  • Knowledge of Ohm's Law and voltage calculations
  • Basic circuit analysis skills, including parallel resistor configurations
NEXT STEPS
  • Study the concept of inductance and its role in circuits
  • Learn how to apply Kirchhoff's laws in circuit analysis
  • Explore the relationship between voltage, current, and resistance in parallel circuits
  • Investigate the effects of different inductance values on current change rates
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Students studying electrical engineering, physics enthusiasts, and anyone looking to deepen their understanding of inductors and circuit dynamics.

machinarium
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Homework Statement



For the circuit shown in Fig. 7, what is the rate of change of the current
in the inductor when the current in the battery is 0.50 A?
(1) 600 A/s (2) 400 A/s (3) 200 A/s (4) 800 A/s (5) 500 A/s

attachment.php?attachmentid=31182&stc=1&d=1294548676.jpg


Homework Equations



i(t)=Imax(1-e-tR/L)
induced emf = L (dI/dt)

The Attempt at a Solution



I didn't fully understand the problem. I don't understand why the current in the battery was given? What would I use that value for?

Please explain to me what I need to know to find out the rate of change of the current. Thank you very much.
 

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Think: How is the voltage across the inductor related to the rate of change of current?

ehild
 
Can you explain to me the whole problem? Please don't ask such a question, I was already very confused.

Thank you.
 
The current through the battery is the same as through the 20 ohm resistor. The voltage across the inductor is the same as across the 10 ohm resistor, as they are connected in parallel. Can you find this voltage?

ehild
 
machinarium said:
I didn't fully understand the problem. I don't understand why the current in the battery was given? What would I use that value for?

Please explain to me what I need to know to find out the rate of change of the current. Thank you very much.

The current through the inductor will be changing with time. As a result, the total current being drawn from the battery will also change with time. By asking what the rate of change of the current through the inductor will be when the current through the battery is a given amount, it is equivalent to asking for the rate of change of the inductor current at a specific moment in time.
 
Ah, I remembered it. Thank you for your commitment, ehild and gneill

The potential through the inductor is 12 – (20 ohm X 0.5 A) = 2 V
Then dI/dt=2V/10mH=200 A/s
Is that correct?
 
The answer is correct.

You might refer to the potential across the inductor, rather than through the inductor; Potentials are "across", currents are "through".
 
gneill said:
You might refer to the potential across the inductor, rather than through the inductor; Potentials are "across", currents are "through".

Potential is defined at a point. Potential difference or voltage is across a resistor or coil, or between two points.

ehild
 
ehild said:
Potential is defined at a point. Potential difference or voltage is across a resistor or coil, or between two points.

ehild

"Across" implies two points are involved. "potential across" is sloppy shorthand for potential difference across. mea culpa.
 

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