Find the real zeros of the function algebraically

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The discussion focuses on finding the real zeros of the polynomial function f(x) = x^3 + 5x^2 + 9x + 45. It highlights the factoring process, where the greatest common factor (GCF) x + 5 is extracted, leading to the equation (x^2 + 9)(x + 5) = 0. Participants clarify that the GCF is a binomial, correcting previous terminology used in the discussion. The confusion arises from the order of terms in the factored expression. Ultimately, the conversation emphasizes the importance of correctly identifying and factoring the GCF in polynomial equations.
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f(x)=x^3+5x^2+9x+45
x^3+5x^2+9x+45=0
x^2(x+5)+9(x-5)=0
(x^2+9)(x+5)=0
What happends to the (x+5)?
 
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swatmedic05 said:
f(x)=x^3+5x^2+9x+45
x^3+5x^2+9x+45=0
x^2(x+5)+9(x-5)=0
There's an error in the step above.
swatmedic05 said:
(x^2+9)(x+5)=0
What happends to the (x+5)?

Since (x2 + 9)(x + 5) = 0, then either x2 + 9 = 0 or x + 5 = 0. Can you continue from here?
 
\begin{aligned}<br /> x^3 + 5x^2 + 9x + 45 &amp;= 0 \\<br /> x^2(x + 5) + 9(x + 5) &amp;= 0 \\<br /> (x^2 + 9)(x + 5) &amp;= 0<br /> \end{aligned}
I'm assuming that the error pointed out above is just a typo, so I'll just fix it. As for
What happened to the (x+5)?
It was the greatest common factor, so it got factored out.

Say you wanted to factor 16x - 28. The GCF is 4, and you could rewrite the expression as
4(4x) - 4(7),
and then factor out the 4 to get
4(4x - 7).

It's the same thing in your problem. The GCF is an expression: x + 5. You factor the x + 5 out in x^2 \bold{(x + 5)} + 9 \bold{(x + 5)} = 0 and you get (x^2 + 9)(x + 5) = 0. Maybe part of the confusion is that the GCF appears last instead of first?69
 
Last edited:
eumyang said:
\begin{aligned}<br /> x^3 + 5x^2 + 9x + 45 &amp;= 0 \\<br /> x^2(x + 5) + 9(x + 5) &amp;= 0 \\<br /> (x^2 + 9)(x + 5) &amp;= 0<br /> \end{aligned}
I'm assuming that the error pointed out above is just a typo, so I'll just fix it. As for

It was the greatest common monomial factor, so it got factored out.
It was the greatest linear factor. It is not a monomial, it is a binomial, just like x^2+ 9.

Say you wanted to factor 16x - 28. The GCF is 4, and you could rewrite the expression as
4(4x) - 4(7),
and then factor out the 4 to get
4(4x - 7).

It's the same thing in your problem. The GCF is an expression: x + 5. You factor the x + 5 out in x^2 \bold{(x + 5)} + 9 \bold{(x + 5)} = 0 and you get (x^2 + 9)(x + 5) = 0. Maybe part of the confusion is that the GCF appears last instead of first?


69
 
Fixed. Didn't mean to use the term "monomial" -- just GCF. This is what you get for replying at 5am. :P69
 

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