Find the resistivity of the resistive wire

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SUMMARY

The resistivity of the resistive wire is calculated using the formula ρ = RA/L, resulting in a value of 3.978×10-6 Ωm. The total resistance (Req) is determined to be 12Ω, leading to a current (I) of 3 A when a voltage of 36V is applied. The charge (ΔQ) transferred over 100 seconds is calculated to be 300 C. Rounding the resistivity value may result in loss of credit in academic settings.

PREREQUISITES
  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with the concept of resistivity in materials
  • Basic knowledge of geometry for calculating length of wire
  • Ability to manipulate and solve algebraic equations
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  • Study the derivation and applications of the resistivity formula ρ = RA/L
  • Learn about the factors affecting resistivity in different materials
  • Explore advanced topics in circuit analysis using Kirchhoff's laws
  • Investigate the implications of rounding in scientific calculations
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Students in physics or electrical engineering, educators teaching circuit theory, and anyone involved in laboratory experiments related to electrical properties of materials.

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Homework Statement


Capture.png


Homework Equations


##ρ=\frac{RA}{L}##
##I=\frac{ΔQ}{Δt}##
##I=\frac{ΔV}{R}##

The Attempt at a Solution


(a)
##ρ=\frac{RA}{L}##
##L=\frac{2*π*r}{2} = πr##
ρ = (5*2.5*10-7)/(π*0.1)
ρ = 4*10-6 Ωm.

(b)
Req = 7+5 = 12Ω
##I=\frac{ΔV}{R}##
I = 36/12 = 3 A
##I=\frac{ΔQ}{Δt}##
3 = ΔQ / 100
ΔQ = 3*100 = 300 C

Is my answer correct ?
 

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Fatima Hasan said:

Homework Statement


View attachment 225595

Homework Equations


##ρ=\frac{RA}{L}##
##I=\frac{ΔQ}{Δt}##
##I=\frac{ΔV}{R}##

The Attempt at a Solution


(a)
##ρ=\frac{RA}{L}##
##L=\frac{2*π*r}{2} = πr##
ρ = (5*2.5*10-7)/(π*0.1)
ρ = 4*10-6 Ωm.

(b)
Req = 7+5 = 12Ω
##I=\frac{ΔV}{R}##
I = 36/12 = 3 A
##I=\frac{ΔQ}{Δt}##
3 = ΔQ / 100
ΔQ = 3*100 = 300 C

Is my answer correct ?
Yes, but the resistivity comes out to be 3.978×10-6 ohm-meter. You might not get full credit if you round that off to 4.
 
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