Find the speed of the descending block

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Homework Help Overview

The problem involves a ring sliding on a horizontal rod, connected by a massless string to a block descending under the influence of gravity. The setup includes a pulley and requires understanding the relationship between the speed of the ring and the speed of the descending block, particularly when the string makes an angle with the horizontal.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the ring and the block, questioning whether the acceleration of the ring in the horizontal direction is the same as the acceleration of the block in the vertical direction. There are suggestions to consider the problem from a kinematic perspective rather than focusing solely on forces.

Discussion Status

Participants are exploring different approaches to the problem, including kinematic relationships and the implications of the angle θ. Some have offered guidance on considering relative velocities and the tautness of the string, while others are still questioning the relationship between the accelerations of the ring and the block.

Contextual Notes

There is uncertainty regarding the relationship between the accelerations of the ring and the block, as well as the implications of the angle θ on their speeds. The discussion reflects a mix of interpretations and approaches to the problem.

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Homework Statement


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So, we have a ring 'A' having mass 'm' that can slide on the horizontal rod. It is attached to a massless string, whose other end is attached to a block of mass 'M = 2m'. 'B' is a massless and frictionless pulley.
The problem states that at an instant, the string between ring and the pulley makes an angle 'θ' with the horizontal rod. If the speed of the ring at that instant is 'v', what will be the speed with which the block C descends.

Homework Equations


Σ Fx = max
∑ Fy = may
∑ Fz = maz

The Attempt at a Solution


I have drawn the free body diagrams listing all the forces.
The forces acting on the ring 'C' are:
Σ Fx = Tcosθ = ma
∑ Fy = N - mg - Tsinθ = 0

Forces acting on the block are:
∑ Fy = T - Mg = Ma' .

That's all I did.

What I don't understand is, will the acceleration due to the X component of tension force, Tcosθ be the same in magnitude as the acceleration a' of the descending block?
 
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NoahCygnus said:

Homework Statement


View attachment 205162
So, we have a ring 'A' having mass 'm' that can slide on the horizontal rod. It is attached to a massless string, whose other end is attached to a block of mass 'M = 2m'. 'B' is a massless and frictionless pulley.
The problem states that at an instant, the string between ring and the pulley makes an angle 'θ' with the horizontal rod. If the speed of the ring at that instant is 'v', what will be the speed with which the block C descends.

Homework Equations


Σ Fx = max
∑ Fy = may
∑ Fz = maz

The Attempt at a Solution


I have drawn the free body diagrams listing all the forces.
The forces acting on the ring 'C' are:
Σ Fx = Tcosθ = ma
∑ Fy = N - mg - Tsinθ = 0

Forces acting on the block are:
∑ Fy = T - Mg = Ma' .

That's all I did.

What I don't understand is, will the acceleration due to the X component of tension force, Tcosθ be the same in magnitude as the acceleration a' of the descending block?
I don't think you need to use forces for this problem (but I could be wrong). They give you the speed of the ring horizontally, and as long as the string stays taut, that will just translate into a change in the length of the string between the pulley and M. Can you try approaching the problem that way?
 
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berkeman said:
I don't think you need to use forces for this problem
Quite so.
@NoahCygnus , these kinematics problems can be confusing. The best way is to think in terms of the component of relative velocity in the direction of the string (or bar, in some questions). How fast is the ring moving towards the pulley?
 
berkeman said:
I don't think you need to use forces for this problem (but I could be wrong). They give you the speed of the ring horizontally, and as long as the string stays taut, that will just translate into a change in the length of the string between the pulley and M. Can you try approaching the problem that way?
I'll try to approach it the way you mentioned. Though I face only one problem , does the acceleration of the ring in x direction have the same magnitude as the acceleration of the block ? Or is it more?
 
NoahCygnus said:
I'll try to approach it the way you mentioned. Though I face only one problem , does the acceleration of the ring in x direction have the same magnitude as the acceleration of the block ? Or is it more?
That's for you to figure out, but I checked my answer by thinking about it intuitively. Say θ is small, so the top part of the string is almost parallel with the bar. What is the speed of the string in relation to the ring at that small angle? And what happens as the ring gets close to directly over M, so the string is vertical and θ = 90 degrees? What is the vertical speed of the string at that point? Does this function remind you of any trig functions...? :smile:
 
NoahCygnus said:
does the acceleration of the ring in x direction have the same magnitude as the acceleration of the block ?
The question as posted involves speeds, not accelerations. But maybe there are more parts to the question?
 
haruspex said:
The question as posted involves speeds, not accelerations. But maybe there are more parts to the question?
Yes, I also has to find the acceleration , which is the easier part. But I can't figure out if the acceleration on the ring in x direction should be the same as that of the block in y direction .
 
NoahCygnus said:
I can't figure out if the acceleration on the ring in x direction should be the same as that of the block in y direction .
Did you try the approach I recommended in post #3? Did you understand it?
 

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