MHB Find the sum of all positive integers a

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The discussion revolves around finding all positive integers \( a \) for which the expression \( \sqrt{\sqrt{(a+500)^2-250000}-a} \) results in an integer. Participants explore the mathematical manipulation of the expression, focusing on simplifying it to identify valid integer solutions. The problem involves analyzing the conditions under which the inner square root yields a non-negative result, leading to specific constraints on \( a \). Through calculations and substitutions, the contributors arrive at potential values of \( a \) and their corresponding sums. Ultimately, the goal is to determine the total sum of all such integers \( a \).
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Find the sum of all positive integers $a$ such that $\sqrt{\sqrt{(a+500)^2-250000}-a}$ is an integer.
 
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anemone said:
Find the sum of all positive integers $a$ such that $\sqrt{\sqrt{(a+500)^2-250000}-a}$ is an integer.

let m=$\sqrt{\sqrt{(a+500)^2-250000}-a}----(*)$

n=$\sqrt{(a+500)^2-250000}< a+500$

$m<\sqrt{500}\,\, or\,\, m\leq 22$---(1)

$n=\sqrt {a(a+1000)}=\sqrt{a(a+2^35^3)}$

min(a)=125=$5^3$

and $\sqrt {250}<m \,\, or \, 16\leq m$----(2)

from (1) and (2) put m=16,17,18,19,20,21,22 to (*)

we get m=20 where $a=800=2^55^2$ is the only solution
 
Last edited:
Albert said:
let m=$\sqrt{\sqrt{(a+500)^2-250000}-a}----(*)$

n=$\sqrt{(a+500)^2-250000}< a+500$

$m<\sqrt{500}\,\, or\,\, m\leq 22$---(1)

$n=\sqrt {a(a+1000)}=\sqrt{a(a+2^35^3)}$

min(a)=125=$5^3$

and $\sqrt {250}<m \,\, or \, 16\leq m$----(2)

from (1) and (2) put m=16,17,18,19,20,21,22 to (*)

we get m=20 where $a=800=2^55^2$ is the only solution

Well done Albert! Thanks for participating.:)
 

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