Find The Sum Of The Convergent Series

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SUMMARY

The convergent series discussed is represented by the formula \(\sum_{n=2}^{\infty} \frac{1}{n^2-1}\). Through partial fraction decomposition, it is identified as a telescoping series. The partial sums reveal a pattern where terms cancel out, leading to a simplified nth partial sum formula of \(\frac{1}{n}\). The confusion arises regarding the derivation of this simplified formula from the telescoping nature of the series.

PREREQUISITES
  • Understanding of telescoping series
  • Familiarity with partial fraction decomposition
  • Basic knowledge of infinite series convergence
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the properties of telescoping series in detail
  • Learn about partial fraction decomposition techniques
  • Explore convergence tests for infinite series
  • Practice deriving nth partial sums for various series
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Students studying calculus, particularly those focusing on series and sequences, as well as educators looking to enhance their teaching methods in mathematical analysis.

Bashyboy
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Homework Statement


\sum_{n=2}^{\infty} \frac{1}{n^2-1}


Homework Equations





The Attempt at a Solution


After doing partial fraction decomposition, I discovered that it was a telescoping series of some sort; the partial sum being 1/2[ (1 -1/3) + (1/2 - 1/4) + (1/3 - 1/4) +...] The only thing I can't do is see the pattern to make a nth partial sum. How would I go about this?
 
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Write out the first few partial sums explicitly. Four or five is probably enough to see how the cancellations work out and which terms are going to stick around.
 
Well, I can see that the 1 and 1/2 would have nothing to cancel out with; but what I can truly see doesn't go beyond that.
 
What specifically is confusing you? Frankly, I don't see how you can not see the pattern after writing out the first handful of partial sums.
 
I attached the solution from the text-book. I don't understand how they get 1/n in the simplified nth partial sum formula.
 

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