Find the sum of the first n terms

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Homework Help Overview

The discussion revolves around finding the sum of the first n terms of a sequence denoted as U1, U2, U3, etc. The specific nature of the sequence is not clearly defined, leading to questions about its terms and behavior.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants attempt to express the sum using a formula and explore the implications of alternating terms in the sequence. Questions arise regarding the definition of the sequence and the nature of its terms.

Discussion Status

There is ongoing exploration of the sequence's properties, with some participants providing insights into the behavior of the sum. Multiple interpretations of the sequence are being considered, and guidance has been offered regarding the formulation of the sum.

Contextual Notes

Participants note the lack of clarity regarding the sequence's terms and the assumptions being made about its behavior. The discussion reflects uncertainty about the exact nature of the problem and the definitions involved.

lionely
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Homework Statement



Find the sum of the first n terms of the sequence U1, U2, U3... Ur

Homework Equations





The Attempt at a Solution



$$ \sum_{r = 1}^n (1 + (-1)^r) = n + (-1)^n $$

But I don't this is right... any help?
 
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lionely said:

Homework Statement



Find the sum of the first n terms of the sequence U1, U2, U3... Ur
What are U1, U2, etc.?
lionely said:

Homework Equations





The Attempt at a Solution



$$ \sum_{r = 1}^n (1 + (-1)^r) = n + (-1)^n $$

But I don't this is right... any help?
 
It doesn't say this is the exact question, it just wants me to find the Sum of the first n terms of this case
 
lionely said:
It doesn't say this is the exact question, it just wants me to find the Sum of the first n terms of this case
Like before, write out the first few terms of the series.
 
It alternates between 1 and -1 so would the sum would alternate between -1 and 0... so... 1/2( (-1)^n -1) ?
 
lionely said:
It alternates between 1 and -1 so would the sum would alternate between -1 and 0... so... 1/2( (-1)^n -1) ?
You said, "It" alternates ...

What is the "It" you refer to?

The series never decreases.


Write out the first several terms of the sequence, then the first several terms of the series.
 
when I mean "it" I meant the sequence. I'm sorry and what I typed above was in reference to the part I did not understand, the sum of (-1)^n. I understand the sum of 1 to n terms = n.

so my final answer is $$ n + 1/2((-1)^n -1)$$
 
lionely said:
when I mean "it" I meant the sequence. I'm sorry and what I typed above was in reference to the part I did not understand, the sum of (-1)^n. I understand the sum of 1 to n terms = n.

so my final answer is $$ n + 1/2((-1)^n -1)$$

That looks pretty good.

S1 = 0

S2 = 2

S3 = 2

S4 = 4

S5 = 4

...
 

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