Geometric Sequence and the Limiting Value

Click For Summary

Homework Help Overview

The discussion revolves around a sequence defined recursively, where participants explore its properties, specifically whether it is geometric and its limiting value as n approaches infinity.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate terms of the sequence and deduce its limiting value, questioning the nature of the sequence as geometric. Some participants confirm the calculations but clarify that the sequence does not meet the criteria for being geometric.

Discussion Status

Participants have engaged in verifying calculations and clarifying the definition of a geometric sequence. There is ongoing exploration of the limiting value, with some participants seeking confirmation of their reasoning.

Contextual Notes

There is a mention of formatting tools available for writing subscripts, which indicates a focus on clarity in mathematical notation. The discussion also reflects uncertainty regarding the classification of the sequence and its limiting behavior.

AN630078
Messages
242
Reaction score
25
Homework Statement
Hello, I have been practising arithmetic and geometric sequences when I came across the problem below but I am not sure whether I have arrived at the correct conclusion, since the values I have determined for the first few terms in the sequence do not have a constant common ratio as defined by un+1/un=r. Have I made a mistake in my calculations?

1. Find the values of u2,u3 and u4 given tht un+1=3-1/3(un) and u1=3
2. Find the limiting value of un as n tends to infinity
Relevant Equations
un+1=3-1/3(un)
1. When n=1,
u1+1=3-1/3(u1)
u2=3-1/3(3)
u2=2

When n=2
u2+1=3-1/3(u2)
u3=3-1/3(2)
u3=7/3

When n=3
u3+1=3-1/3(u3)
u4=3-1/3(7/3)
u4=20/9

The common ratio is defiend by r=un+1/un, but this is different between the terms, i.e. u2/u1=2/3 whereas u3/u2=(7/3)/2=7/6
Have I made a mistake?

2. A sequence u1, u2, u3... converges to a limit L as the terms get ever closer to L. If the limit of un as n → ∞ is L, the terms un and un+1 are approximately equal to L.
un+1=3-1/3(un)
Replace un+1 and un with L in the equation.
L=3-1/3L
4/3L=3
4L=9
L=9/4

Thus, the limiting value of the sequence is 9/4. Would this be correct?
 
Physics news on Phys.org
Your calculations are correct.

The sequence is not geometric; if it were it would satisfy u_{n+1} = \lambda u_n rather than u_{n+1} = \lambda u_n + c.
 
  • Like
Likes   Reactions: AN630078
In the top toolbar there should be a ...∨ sign which allows you to write subscipts.
 
  • Like
Likes   Reactions: AN630078
pasmith said:
Your calculations are correct.

The sequence is not geometric; if it were it would satisfy u_{n+1} = \lambda u_n rather than u_{n+1} = \lambda u_n + c.
Thank you for your reply. Oh ok thank you for the clarification, would my solution for the limiting value also be correct? 😊
 
epenguin said:
In the top toolbar there should be a ...∨ sign which allows you to write subscipts.
I have just looked in the toolbar and have seen what you mean, in addition to the option to insert symbols. Thank you for the suggestion, that is so useful and will definitely allow me to type in a more readable format 👍
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
1
Views
17K
Replies
4
Views
7K
  • · Replies 1 ·
Replies
1
Views
1K