Find the tensions in the strings

  • Thread starter Thread starter MyNewPony
  • Start date Start date
  • Tags Tags
    Strings
Click For Summary
SUMMARY

The discussion focuses on calculating the tensions in two strings connected to objects of equal mass m rotating around a shaft with a constant angular velocity ω. The first object is positioned at a distance d from the axis, while the second is at a distance 2d. The tension in the first string is derived as T = m(ω²d), and for the second string, it is T = m(ω²(4d²)). The analysis confirms that tension opposes centripetal acceleration and is directly proportional to the radius and angular velocity squared.

PREREQUISITES
  • Understanding of centripetal force and acceleration
  • Familiarity with angular velocity and its implications
  • Knowledge of Newton's second law (F = ma)
  • Basic concepts of rotational motion
NEXT STEPS
  • Study the relationship between angular velocity and centripetal force in rotating systems
  • Explore the effects of varying mass and distance on tension in strings
  • Learn about the dynamics of multiple objects in rotational motion
  • Investigate the role of tangential and centripetal acceleration in circular motion
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of rotational systems and tension in strings.

MyNewPony
Messages
30
Reaction score
0

Homework Statement



Two objects of equal mass m are whirling around a shaft with a constant angular velocity ω. The first object is a distance d from the central axis, and the second object is a distance 2d from the axis. You may assume the strings are massless and inextensible. You may ignore the effect of gravity. Find the tensions in the two strings.

Homework Equations



F(net) = ma
α = ω^2*r
a = αr

The Attempt at a Solution



First string:

If gravity is ignored, the only force acting on the object is tension. Thus,

T = ma

and

T = m(ω^2*d^2)

Second string:

T = ma

and

T = m(ω^2*(2d)^2)
T = m(ω^2*4d^2)

Are there any other forces acting on the objects?
 
Physics news on Phys.org
Well you know that the tension will oppose the centripetal acceleration and that the centripetal force will equal the tension. Therefore you are close T=m(w^2*r) where w means omega, or angular velocity, and r is the radius. Just don't square the radius it gets canceled out in the math.
 
Your tangential acceleration |a| is related to |α|*r.

But a is not directed along the string. They are orthogonal. It's α that is directed along the string.

The tension in the string then is given simply by

T = m*ω2*r
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
21
Views
2K
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
1
Views
2K