1. The problem statement, all variables and given/known data A battery with = 12.0 V and internal resistance r = 1.0 Ω is connected to two 6.9 kΩ resistors in series. An ammeter of internal resistance 0.50 Ω measures the current, and at the same time a voltmeter with internal resistance 10.0 kΩ measures the voltage across one of the 6.9 kΩ resistors in the circuit. What do the ammeter and the voltmeter read? 2. Relevant equations V=IR 3. The attempt at a solution So I found the ammeter reading where Itotal=1.09mA which was correct. For the voltmeter reading, I got: V=Itotal*6.9kΩ=7.52V which was incorrect. Anyone care to help?