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## Homework Statement

A battery with

*r*= 1.0 Ω is connected to two 6.9 kΩ resistors in series. An ammeter of internal resistance 0.50 Ω measures the current, and at the same time a voltmeter with internal resistance 10.0 kΩ measures the voltage across one of the 6.9 kΩ resistors in the circuit. What do the ammeter and the voltmeter read?

## Homework Equations

V=IR

## The Attempt at a Solution

So I found the ammeter reading where I

_{total}=1.09mA which was correct.

For the voltmeter reading, I got:

V=I

_{total}*6.9kΩ=7.52V which was incorrect. Anyone care to help?