- #1

Angie K.

- 108

- 1

## Homework Statement

A 2.44-kΩ and a 4.92-kΩ resistor are connected in parallel; this combination is connected in series with a 1.12-kΩ resistor. If each resistor is rated at 1/2 W, what is the maximum voltage that can be applied across the whole network?

## Homework Equations

P=V^2/Req

V=I*R

## The Attempt at a Solution

I solved for the equivalent resistance.

I converted the kΩ to Ω and used the equation for parallel resistors

1/R1,R2 = (1/R1)+(1/R2) = 1/2440 + 1/4920 = 6.1308E-4

R1,2 = 1/6.1308E-4 = 1631.086957 Ohms

then R123 = R1,2+R3 = 1631.086957+1120 = 2751.086957 Ohms

Then I used P=V^2/Req

1/2=V^2/2751.086957

V=23.6643 V (which should be the maximum voltage since parallel resistors have the same voltage throughout)

But it's wrong and I'm not sure where I messed up?