Find the work done by nonconservative forces in stopping the plane.

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SUMMARY

The work done by nonconservative forces in stopping an 18,000 kg airplane landing at 92 m/s on a 115 m stationary aircraft carrier deck is calculated using energy considerations. The kinetic energy (KE) of the plane before landing is determined using the formula KE = 1/2(m)(v)^2, resulting in a value of -7.6 x 10^7 J. This indicates that the nonconservative forces performed negative work, reflecting energy loss during the stopping process.

PREREQUISITES
  • Understanding of kinetic energy calculations
  • Familiarity with the work-energy principle
  • Basic knowledge of physics units (joules, kilograms, meters per second)
  • Ability to apply the formula W = FD in context
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn about nonconservative forces and their effects on mechanical systems
  • Explore examples of energy loss in real-world applications
  • Investigate the implications of significant figures in physics calculations
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Students in physics, educators teaching mechanics, and anyone interested in understanding energy transformations in dynamic systems.

stuckne1
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Homework Statement


Find the work done by nonconservative forces in stopping the plane.

A 18000 {\rm kg} airplane lands with a speed of 92 {\rm m/s} on a stationary aircraft carrier deck that is 115 {\rm m} long.


Homework Equations


W = FD


The Attempt at a Solution



18000 * 92 * 115 = 190440000 J

Unless it's wanting 1.9 * 10^8 = 190000000 J (which seems wrong since detail is lost)

(I don't think that's 2 significant digits.)
 
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stuckne1 said:

Homework Statement


Find the work done by nonconservative forces in stopping the plane.

A 18000 {\rm kg} airplane lands with a speed of 92 {\rm m/s} on a stationary aircraft carrier deck that is 115 {\rm m} long.


Homework Equations


W = FD


The Attempt at a Solution



18000 * 92 * 115 = 190440000 J

Unless it's wanting 1.9 * 10^8 = 190000000 J (which seems wrong since detail is lost)

(I don't think that's 2 significant digits.)

The best way to solve this type of problem is with energy considerations. What was the KE of the plane just before it traps on the carrier deck? What is the KE right after it is stopped by the wire? Wher did that energy go?
 
it was 1/2(m)(v)^2 or something.

The answer was -7.6 x 10 ^7

Thanks!
 
stuckne1 said:
it was 1/2(m)(v)^2 or something.

The answer was -7.6 x 10 ^7

Thanks!

Does that mean that you calculated the correct answer? What are the units of the answer?
 
Yes, the units of the correct answer was in joules.
 

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