Find the zeroes of r. What to do when it is a multiple of theta?

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Discussion Overview

The discussion revolves around solving the equation for zeroes of r when the angle is a multiple of theta, specifically in the context of polar coordinates. Participants explore the implications of having a term like (2theta) in the equation r=5+10cos(2theta) and how to approach solving it.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses understanding of solving for theta when it appears alone, but questions how to handle the case when it is (2theta).
  • Another participant suggests that the equation can be set to zero, specifically mentioning the equation 5 + 10cos(2theta) = 0.
  • A participant proposes that without the 2*theta, they would set the equation equal to zero and solve for cos(theta), but is uncertain about how to proceed with the multiple angle.
  • There is a suggestion to solve for 2*theta first and then derive theta from that solution.
  • One participant questions whether to multiply -1/2 by 2 or add 2pi in their calculations, indicating uncertainty in the approach.
  • A later reply references the value of having a textbook for examples of solving trigonometric equations involving angle multiples.

Areas of Agreement / Disagreement

Participants express varying levels of understanding and approaches to the problem, with no clear consensus on the method to solve the equation involving (2theta). Uncertainty remains about the correct steps to take.

Contextual Notes

Participants do not clarify specific assumptions or definitions regarding the handling of angle multiples in trigonometric equations, and the discussion includes unresolved mathematical steps.

Tyrion101
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I understand what to do when theta is by itself such as r=5+10cos(theta) but what if you have the same equation, and it is (2theta) I am on taptalk by the way.
 
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Tyrion101 said:
I understand what to do when theta is by itself such as r=5+10cos(theta) but what if you have the same equation, and it is (2theta) I am on taptalk by the way.
What have you tried?
In essence, you're trying to solve the equation ##5 + 10\cos(2\theta) = 0##.
 
Last edited:
Well if it were without the 2*theta I'd set it equal to 0, like you did, and solve for cos(theta). Well anyway without the 2 you turn the equation into cos=-1/2, would I just multiply -1/2 by 2? Or would I add 2pi or something?
 
Solve for 2*theta. Solve for theta from that.
 
Tyrion101 said:
Well if it were without the 2*theta I'd set it equal to 0, like you did, and solve for cos(theta). Well anyway without the 2 you turn the equation into cos=-1/2, would I just multiply -1/2 by 2? Or would I add 2pi or something?
You took a trig class, right? Do you still have your textbook? If so, there should be numerous examples of solving trig equations, including ones that involve the sine or cosine (or other trig function) of angle multiples.
 

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