Find the zeros of the function algebraically

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Homework Help Overview

The discussion revolves around finding the zeros of two functions: a rational function f(x) = x/(9x^2 - 4) and a cubic function f(x) = x^3 - x. The original poster expresses uncertainty due to a recent absence from class.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to solve the first function by manipulating the equation but questions their approach after checking the answer in the back of the book. For the second function, they express a lack of understanding of how to find zeros of a cubic function. Other participants suggest focusing on the numerator for the first function and factoring for the second.

Discussion Status

Participants are actively engaging with the original poster's attempts, providing guidance on the methods to approach the problems. There is a mix of interpretations regarding the steps taken, particularly in the second function, with some clarifications being offered.

Contextual Notes

The original poster indicates a gap in their understanding due to missing class, which may affect their grasp of the material. There is also a mention of a potential error in the formulation of the second function, which has led to some confusion in the discussion.

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Homework Statement


Find the zeros of the function algebraically


Homework Equations


f(x)=x/(9x^2-4)
and
f(x)=x^3-x

The Attempt at a Solution


i was gone for about a month and a half from the class because i had to move and I am kinda rusty
ATTEMPT-

f(x)=x/(9x^2-4)
Multiplied by x
subtracted 9x^2
and added 4, which gave me...
-9x^2+x+4=f(x) then i put it in a quadratic formula to find it and i got the wrong answer (i checked in the back of the book for the answer which was 0, i know I am probly really wrong but i was away from the class a long time lol.

Second problem
f(x)=x^3-x
I honestly completely forgot how to solve for the zeros of a cubic function sorry :(
 
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For the first one, the only time a rational expression (e.g., x/(9x^2 - 4)) can be zero is when the numerator is zero.

PanTh3R said:
f(x)=x/(9x^2-4)
Multiplied by x
subtracted 9x^2
and added 4, which gave me...
This doesn't make any sense.
 
For the 2nd problem, factor x^3 - x.

Frankly, missing a month and a half of a math class, regardless of whether the reason is good or not, might be insurmountable.
 
oops i put in the problem wrong and i figured it out(the second one)
f(x)=1/2x^3-x
x(1/2x^2-1)=0
x=0
1/2x^2-1=0
1/2x^2=1
x^2=2
x= +-square root of 2

Thank you for your assistance.
 
Watch out on that second equation... you forgot about the x you factored out.

A cubic equation has three zeros.
 
Char. Limit said:
Watch out on that second equation... you forgot about the x you factored out.

No he didn't! :smile:



it would suck if the OP were a girl. Still, I prefer assuming than typing in he/she.
They should really create a word to indicate either sex!
 

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