The time a ball launched upward at an initial speed of 18 m/s remains in the air can be calculated using the Kinematic Equations of Motion for constant acceleration. Specifically, the relevant equation is derived from the principles of uniformly accelerated motion, where the acceleration due to gravity is approximately -9.81 m/s². The total time in the air can be determined by calculating the time to reach the peak and doubling it, as the ascent and descent times are equal in the absence of air resistance.
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iac0b said:A ball is launched directly upward from ground level with an initial speed of 18 m/s. (Air resistance is negligible.)
What equation would I use to find the time the ball was in the air?