Find two possible values of ##z## in the complex number problem

[chwala]

Homework Statement

see attached.

Relevant Equations

complex numbers

ok here i have,
$x^2+y^2-5x=0$
$-y= 2$
I end up with the quadratic equation, $x^2-5x+4=0$

Finally giving us, $z=4-2i$ and $z=1-2i$

 

[PeroK]

Looks right.

 

[Mark44]

Homework Statement:: see attached.
Relevant Equations:: complex numbers

Finally giving us s, $z=4-2i$ and $z=1-2i$

Which is easy enough to check for yourself.

 

[chwala]

Thanks Mark...I am seeking for a different way of solving this apart from simultaneous approach that I used...that's why I posted the question...yes, I can check that mate.

 

[DaveE]

Thanks Mark...I am seeking for a different way of solving this apart from simultaneous approach that I used...that's why I posted the question...yes, I can check that mate.

Then you should ask for a different approach, which you haven't gotten from us yet. This wasn't clear in your original post.

 

[Mark44]

Thanks Mark...I am seeking for a different way of solving this apart from simultaneous approach that I used...that's why I posted the question...yes, I can check that mate.

What you did was the most obvious and simplest approach. If there is another way, I can't think what it might be.

 

[chwala]

Noted Mark...thanks for your time on this...