Find two possible values of ##z## in the complex number problem

Click For Summary

Homework Help Overview

The problem involves finding possible values of the complex number ##z##, derived from equations related to complex numbers. The original poster presents a quadratic equation resulting from their calculations.

Discussion Character

  • Exploratory, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the original poster's use of a simultaneous approach to solve the problem and express a desire for alternative methods. There is mention of checking the results obtained.

Discussion Status

The discussion includes acknowledgment of the original poster's findings, but there is no explicit consensus on alternative methods. Some participants suggest that the approach taken may be the simplest, while others seek different perspectives.

Contextual Notes

There is an indication that the original poster may not have clearly communicated their request for alternative methods in their initial post.

chwala
Gold Member
Messages
2,828
Reaction score
425
Homework Statement
see attached.
Relevant Equations
complex numbers
1646186250510.png
ok here i have,
##x^2+y^2-5x=0##
##-y= 2##
I end up with the quadratic equation, ##x^2-5x+4=0##

Finally giving us, ##z=4-2i## and ##z=1-2i##
 
Physics news on Phys.org
Looks right.
 
  • Like
Likes   Reactions: chwala
chwala said:
Homework Statement:: see attached.
Relevant Equations:: complex numbers

Finally giving us s, ##z=4-2i## and ##z=1-2i##
Which is easy enough to check for yourself.
 
  • Like
Likes   Reactions: chwala
Thanks Mark...I am seeking for a different way of solving this apart from simultaneous approach that I used...that's why I posted the question...yes, I can check that mate.
 
chwala said:
Thanks Mark...I am seeking for a different way of solving this apart from simultaneous approach that I used...that's why I posted the question...yes, I can check that mate.
Then you should ask for a different approach, which you haven't gotten from us yet. This wasn't clear in your original post.
 
  • Like
Likes   Reactions: chwala
chwala said:
Thanks Mark...I am seeking for a different way of solving this apart from simultaneous approach that I used...that's why I posted the question...yes, I can check that mate.
What you did was the most obvious and simplest approach. If there is another way, I can't think what it might be.
 
Noted Mark...thanks for your time on this...
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 22 ·
Replies
22
Views
1K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K
Replies
9
Views
2K
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K