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Answer: upper bound = {[(n+1)^(n+1)]/[(m+1)^(m+1)]}*e^(-(n-m))

lower bound = [(n^n)/(m^m)]*e^(-(n-m))

This is from a chapter on finding bounds for sum of series. Can someone please explain how to arrive at the answer? Thanks!

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- Thread starter mathvision
- Start date

- #1

- 5

- 0

Answer: upper bound = {[(n+1)^(n+1)]/[(m+1)^(m+1)]}*e^(-(n-m))

lower bound = [(n^n)/(m^m)]*e^(-(n-m))

This is from a chapter on finding bounds for sum of series. Can someone please explain how to arrive at the answer? Thanks!

- #2

uart

Science Advisor

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