Find upper and lower bounds for n!/m!

  • Thread starter mathvision
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If n>m>1, find upper and lower bounds for n!/m!

Answer: upper bound = {[(n+1)^(n+1)]/[(m+1)^(m+1)]}*e^(-(n-m))
lower bound = [(n^n)/(m^m)]*e^(-(n-m))

This is from a chapter on finding bounds for sum of series. Can someone please explain how to arrive at the answer? Thanks!
 

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  • #2
uart
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