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Find upper and lower bounds for n!/m!

  1. Sep 12, 2012 #1
    If n>m>1, find upper and lower bounds for n!/m!

    Answer: upper bound = {[(n+1)^(n+1)]/[(m+1)^(m+1)]}*e^(-(n-m))
    lower bound = [(n^n)/(m^m)]*e^(-(n-m))

    This is from a chapter on finding bounds for sum of series. Can someone please explain how to arrive at the answer? Thanks!
  2. jcsd
  3. Sep 12, 2012 #2


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