Find V(f) for two particles resting (and compressing) against a spring.

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SUMMARY

The problem involves two particles, m1 = 2.2 kg and m2 = 4.5 kg, compressing a spring with a spring constant k = 395 N/m by 0.15 m. The conservation of momentum and energy equations are applied to find the final velocities of the particles. The derived equations yield v1 = 1.17 m/s and v2 = 0.611 m/s. The user encountered issues with incorrect answers, suggesting a need to verify the substitution of values in the equations.

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Homework Statement


Two particles of mass m1= 2.2 kg and mass m2 = 4.5 kg that are free to move on a horizontal track are initially held at rest so that they compress a spring as shown in the figure below. The spring has a spring constant k = 395 N/m and is compressed 0.15 m. Find the final velocities of the two particles.


Homework Equations



M1V1=M2V2

1/2M1V1^2 + 1/2M2V2^2 = 1/2 kx^2


The Attempt at a Solution



I am copy/paste a solution for the problem that is exactly what I did but with different numbers.

Conservation of momentum:
m1 v1 + m2 v2 = 0 ...(1)

Conservation of energy:
m1 v1^2 / 2 + m2 v2^2 / 2 = kx^2 / 2
m1 v1^2 + m2 v2^2 = kx^2 ...(2)

From (1):
v2 = - m1 v1 / m2

Substituting for v2 in (2):
m1 v1^2 + m1^2 v1^2 / m2 = kx^2

m1 m2 v1^2 + m1^2 v1^2 = k m2 x^2
m1(m1 + m2)v1^2 = k m2 x^2
v1^2 = k m2 x^2 / [ m1(m1 + m2) ]

v1 = sqrt{ 395 * 4.4 * 0.11^2 / [ 2.3(2.3 + 4.4) ] }
v1 = 1.17 m/s to 3 sig. fig.

Similarly:
v2^2 = k m1 x^2 / [ m2(m1 + m2) ]

v2 = sqrt{ 395 * 2.3 * 0.11^2 / [ 4.4(2.3 + 4.4) ] }
v2 = 0.611 m/s to 3 sig. fig.


I did this and my answer is incorrect.


I ALSO tried:

0.5*k*x^2 = 0.5*m1*v1^2
0.5*k*x^2 = 0.5*m2*v2^2

and THAT was incorrect. I'm in the dark here.


By the way, this is my first post, though I've been browsing PF all semester! Thanks for all the previous help =)
 
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Oh, I forgot to speak of the figure:

0~~~O Two figures are compressing a spring .15 m.
 
Your algebra looks good to me. Check the part where you plug in values, though.
 

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