Derive the formula for the frequency of a spring

[astroman707]

Homework Statement

Two masses m1 and m2 are joined by a spring of spring constant k. Show that the frequency of vibration of these masses along the line connecting them is
ω = √[ k(m1 + m2) / (m1*m2) ]
(Hint: Center of mass remains at rest.)

Homework Equations

f = w/2π
w = √(k/m)
F = -kx
a = - w²x

The Attempt at a Solution

I tried finding the center of mass and using that as m, in ma = kx
I also tried manipulating the formula for acceleration, and plugging it into hooke's law, but that didn"t seem right either. I'm pretty lost to be honest.

 

[Andrew Mason]

I take it that you know that for a fixed spring on one end and a mass m on the other that the frequency of oscillation is $\omega = \sqrt{\frac{k}{m}}$

If you try to work it out as if one of the masses was fixed and another notional mass vibrating relative to it such that the acceleration of that mass is equal to the relative acceleration between the two masses m1 and m2, you can solve the problem. Call the notional single mass that is vibrating $\mu$. If you set $\mu a_{rel} = -kx$ where $a_{rel} = a_2 - a_1$, you can see that $\omega = \sqrt{\frac{k}{\mu}}$. You just have to determine what $\mu$ is. (hint: by Newton's third law $m_1a_1 = - m_2a_2$)

AM

 

[collinsmark]

Hello @astroman707,

'Just curious, is this problem from coursework that requires calculus or differential equations?

Anyway, there's another way to approach this problem if you don't wish to use relative accelerations.

The first order of business is to define your displacements and then relate them to the stretch of the spring. For example, if you choose to define that x_1 is positive when m_1 moves to the left and x_2 is positive when m_2 moves to the right, then x = x_1 + x_2. On the other hand, if you want to define positive in the same x-direction for both, then there will be a negative sign in your equation somewhere (e.g., x = x_2 - x_1). Anyway, the choice is yours, but you'll need to define your terms before we move on.

With that, you should have enough to form two differential equations, one for each mass, by using Newton's second law. But don't worry, you'll only need to use one of them.

The trick then is to use the hint that @Andrew Mason made in the previous post. You're interim goal is to find a relationship of the ratio \frac{x_1}{x_2} in terms of m_1 and m_2. Andrew's hint about Newton's third law will get you there.

After that, do a little substitution and you'll have all you need to solve either of the second order, ordinary differential equations and you'll have your \omega.

 

[Andrew Mason]

If you use Collinsmark's approach you have to keep in mind that $x_1$ and $x_2$ are the respective displacements of $m_1$ and $m_2$ from the centre of mass of the two-body system.

AM