Find Value of a & Point of Intersection for Lines r1 & r2

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Homework Help Overview

The problem involves finding the value of a parameter and the point of intersection for two lines, r1 and r2, represented in vector form. The lines are given with parameters lambda and mu, and the task is to determine the conditions under which they intersect.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss rewriting the lines in parametric and Cartesian forms to compare components. There are attempts to substitute parameters and equate components to find the value of a and the intersection point.

Discussion Status

Some participants have proposed values for a and the intersection point, while others are checking these results. There is an acknowledgment of mistakes in calculations and layout, indicating an ongoing exploration of the problem.

Contextual Notes

Participants are working under the assumption that the lines intersect and are exploring the implications of this assumption on the values of the parameters involved.

lemon
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1. Given that the two lines r1 and r2 intersect, find the value of a and hence determine the point of intersection.
r1=i+9j-3k+landa(i+j-k)
r2=4i+ak+mew(6i+5j+k)




Homework Equations





3. I'm a little lost with this one. Do I need to rewrite in parametric form and then cartesian form then compare i and j components. Then find values of mew and landa. Then use r1 and plug in landa value and solve for point of intersection?
 
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Using this technique I get a=-6
and point of intersection is -52i-45j-12k

Could somebody check this please?
 
At a point of intersection, r1 = r2,
so <1 + s, 9 + s, -3 -s> = <4 + 6t, 0 + 5t, a + t>
(I have dispensed with "landa" (lambda) and "mew" (mu), and replaced them with s and t.)
For two vectors to be equal, their corresponding components must be equal.

The value I get for a is 78.
 
yes thank you. I made a mistake in my layout. I have 78 now.
and
4i+ak-12(6i+5j+k)
4i+78k-72i-60j-12k
which gives -34i-30j+33k
 

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