Find velocity of a moment before terminal velocity is reached?

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SUMMARY

The discussion revolves around calculating the acceleration of a sky diver at specific velocities before reaching terminal velocity. Given the gravitational acceleration of 9.8 m/s² and a diver's mass of 69 kg, the acceleration at 39 m/s was determined to be 5.0468 m/s². Additionally, the diver's velocity of 34.2 m/s at a 56° angle below horizontal raises questions about calculating acceleration at that point. Participants seek clarification on the methodology to arrive at these results.

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trivk96
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Homework Statement


Given g = 9.8 m/s
2
.
A sky diver of mass 69 kg jumps from a
slowly moving aircraft and eventually reachesher terminal velocity 56 m/s.
What was (the magnitude of) her acceleration at the moment her velocity was only
v1 = 39 m/s (directed vertically down)?
Answer in units of m/s2
I got the answer to this as 5.0468


Now consider the same sky diver jumping out
of a faster airplane. At some point before she
reaches her terminal velocity, she has velocity
~v2 of magnitude 34.2 m/s in the direction 56◦
below hirizontal.
What is the magnitude of the sky diver’s
acceleration at that point in time?
Answer in units of m/s2

i have no idea how to do this one. Can someone show me how or point me in the right direction

Homework Equations





The Attempt at a Solution

 
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trivk96 said:

Homework Statement


Given g = 9.8 m/s
2
.
Is there something missing here ↑↑↑ perhaps due to mis-editing?
A sky diver of mass 69 kg jumps from a
slowly moving aircraft and eventually reachesher terminal velocity 56 m/s.
What was (the magnitude of) her acceleration at the moment her velocity was only
v1 = 39 m/s (directed vertically down)?
Answer in units of m/s2
I got the answer to this as 5.0468
Can you show your working so we can see how you did it? I don't get that answer.
 

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