Find Velocity when Acceleration Vs Time Graph

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To find the particle's velocity at 7 seconds using the acceleration vs. time graph, the area under the curve must be calculated, considering both positive and negative areas. The participant expresses confusion about how to handle the areas, particularly regarding the negative area below the axis. They attempt integration but are unsure if they should add the areas from different segments of the graph. Clarification is sought on whether to treat the area of the triangle and rectangle separately or combine them. Understanding the concept of negative area is essential for accurately determining the velocity at the specified time.
dgales4130
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Homework Statement


Find the particles Velocity at 7 seconds . ( Graph Below)

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Homework Equations


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The Attempt at a Solution



T=5 from 7-2
or
T=2 From 7-5 ( Because It's now -a)

I tried int from 0 to 5 -10dt and got -50
then AT=v with both
A @ 7 second = (-20*2)/2 = -20

Is velocity not negative.
I am really embarrassed to ask for help. I would love to understand , and maybe remind me some how science is fun ..
 

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I will assume you are familiar with differentiation since it's listed under relavant equations. Do you know integration yet? If not, think about the graph of a constant acceleration - how do you find the velocity of a constant acceleration versus time graph?
 
Yes , I am comfortable with doing integration.

In this case I am not sure what is area. I know that area is from t 0 - 5 is on the positive side . I am not sure if I should add the two areas to find the v at 7s or something else.

I haven't had I chance to talk about negative area to so it's just a bunch of assumitions , which I don't like.

So , Should I find the area of the partial triangle then the other one below axis ?

Or something else ?
 
If I just do are both on the positive side and negative side of the a axis i get the quantities

20 ( t , 1-2 ; up tri )
20 (t 1-2 ; below rectangle )
45 (t 2-5 ; large tri )
20 ( t 5-7 ; tri in 4 quadrant ) ( is this positive or negative area )
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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