Find Velocity when Acceleration Vs Time Graph

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dgales4130
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Homework Statement


Find the particles Velocity at 7 seconds . ( Graph Below)

Graph titled Particle C of acceleration a_x (m/s^2) against time t (s), showing a line rising from 0 at t=0 to 30 at t=2, falling to -30 at t=6, then flat at -30 until t=8.

Homework Equations


Reference sheet of kinematics equations: instantaneous velocity v = ds/dt, instantaneous acceleration a = dv/dt, final position and final velocity integral forms, and uniformly accelerated motion equations.


The Attempt at a Solution



T=5 from 7-2
or
T=2 From 7-5 ( Because It's now -a)

I tried int from 0 to 5 -10dt and got -50
then AT=v with both
A @ 7 second = (-20*2)/2 = -20

Is velocity not negative.
I am really embarrassed to ask for help. I would love to understand , and maybe remind me some how science is fun ..
 
Attachments
  • Acceleration versus time graph titled Particle C: a_x (m/s²) against t (s), rising linearly from 0 to 30 at t = 2 s, then falling linearly to -30 near t = 8 s, then flat at -30.
    Capture.JPG
    3.1 KB · Views: 766
  • Reference sheet of kinematic equations: instantaneous velocity v = ds/dt, instantaneous acceleration a = dv/dt, final position and final velocity integrals, and uniformly accelerated motion equations v = v0 + at, s = s0 + v0t + (1/2)a t^2, v^2 = v0^2 + 2as.
    Motion Equations.JPG
    24.6 KB · Views: 815
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I will assume you are familiar with differentiation since it's listed under relavant equations. Do you know integration yet? If not, think about the graph of a constant acceleration - how do you find the velocity of a constant acceleration versus time graph?
 
Yes , I am comfortable with doing integration.

In this case I am not sure what is area. I know that area is from t 0 - 5 is on the positive side . I am not sure if I should add the two areas to find the v at 7s or something else.

I haven't had I chance to talk about negative area to so it's just a bunch of assumitions , which I don't like.

So , Should I find the area of the partial triangle then the other one below axis ?

Or something else ?
 
If I just do are both on the positive side and negative side of the a axis i get the quantities

20 ( t , 1-2 ; up tri )
20 (t 1-2 ; below rectangle )
45 (t 2-5 ; large tri )
20 ( t 5-7 ; tri in 4 quadrant ) ( is this positive or negative area )
 
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