Find volume when curve rotated about y-axis

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SUMMARY

The discussion focuses on calculating the volume of the solid formed by rotating the curve defined by the equation \(y = -4 \ln x\) around the y-axis, specifically for the range \(0 \leq y \leq 2\). The user, Deus Abs, utilized GeoGebra for their calculations and arrived at a solution of approximately \(3.97\) after addressing repeated errors in their approach. The conversation emphasizes the importance of adopting a mindset of skepticism and seeking external validation to catch mistakes in mathematical work.

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DeusAbscondus
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Hi folks, could someone please take a look at this for me:

Here are the givens:

$$\text{ Find the volume when this curve is rotated about the y-axis }$$
$$y=-4lnx\ \text{ where } 0\le y \le 2$$

I have set my working out in a geogebra file, taken a screenshot and attached same below.

Would someone kindly take a look at my calculations and point out where I am going astray?

Really appreciate your time,
Deus Abs
 
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e^{0}\ne 0

Good work otherwise.
 
Last edited:
tkhunny said:
e^{0}\ne 0

Good work otherwise.

Thank you kindly!

so: $$-2.2114547+2\pi \approx 3.97$$

Which is the solution given!

Do you know I kept making that error over and over again, through a frustrating hour or so; this makes me *sure* that I must find a different approach (different mind-set/attitude, perhaps) my checking procedure: cultivate an attitude of radical skepticism: something like: "question *everything* again regarding your working assumptions!"

Regs,
D'Abs
 
Contrary to the too broad definition of privacy, another pair of eyes often is quite beneficial. :)
 
Very true! Oftentimes when I make an error like that, I will keep blindly making it over and over, and the best thing for me is to move on to something else, and when I come back to it after a break, then I am much more likely to catch the error. If I don't, then I will seek another pair of eyes! ;)
 

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