Find which value of x horizontal Tangent Line

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SUMMARY

The discussion focuses on finding the value of x where the function F(x) = -4/(x-3)(x+4) has a horizontal tangent line. Participants confirm that to determine this, one must set the derivative F'(x) equal to zero. While the quotient rule is a common method for finding the derivative, the chain rule is also applicable. The key takeaway is to derive F'(x) and solve the equation F'(x) = 0 to find the critical points where the tangent line is horizontal.

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  • Understanding of calculus concepts, specifically derivatives
  • Familiarity with the quotient rule and chain rule for differentiation
  • Knowledge of horizontal tangent lines and their significance in calculus
  • Ability to solve equations involving derivatives
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  • Practice using the quotient rule with different rational functions
  • Explore the chain rule through various composite functions
  • Learn how to analyze critical points and their implications on function behavior
  • Study the graphical interpretation of horizontal tangent lines in calculus
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Students studying calculus, particularly those focusing on derivatives and tangent lines, as well as educators looking for examples of derivative applications in real-world scenarios.

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Find which value of x...horizontal Tangent Line

Homework Statement


What is given is F(x)= -4/(x-3)(x+4) and the problem asks for to find the value of x where f(x) has a horizontal tangent line.

Homework Equations


I read somewhere else on these forms that using the quotient rule is the key, and that you make F'(x) to be equal to 0. If this is correct, I need some clarification on how it'd be put into the formula.
 
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Well yes a horizontal tangent line, means that the gradient of the tangent at that point is zero, so F'(x)=0.

But you don't necessarily need to use the quotient rule, the chain rule would suffice as well.


So first find, F'(x)
 


rock.freak667 said:
Well yes a horizontal tangent line, means that the gradient of the tangent at that point is zero, so F'(x)=0.

But you don't necessarily need to use the quotient rule, the chain rule would suffice as well.


So first find, F'(x)
So, that means the left side is euqal to zero, or is every where (including left side) that is f '(x) is equal to zero. Or, am I looking for the derivative, but anywhere in the formula I see that has f ' (x) is simply zero. Thanks in advance.
 


Just find the expression for F'(x) and just equate that expression to zero and solve for x.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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