Find Width of Slit for Diffraction Maxima

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    Diffraction Maxima
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Homework Help Overview

The problem involves calculating the width of a single slit based on the diffraction pattern produced by laser light of a specific wavelength. The setup includes a screen positioned at a known distance from the slit, and measurements of the distance between diffraction maxima are provided.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply formulas related to diffraction to find the slit width, using both maxima and minima equations. Some participants question the accuracy of the formula used for maxima, suggesting that it may not be precise.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the diffraction equations. Some guidance has been offered regarding the differentiation of intensity expressions, but no consensus has been reached on the correct approach to take.

Contextual Notes

Participants are discussing the implications of using approximations in the equations for maxima and minima, and there may be constraints related to the assumptions made in the original poster's calculations.

Seigi Yokota
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Homework Statement


A single slit diffracts laser light of wavelength 650 nm onto a screen 2.00 m away. The distance between the two first-order maxima on either side of the central peak is 2.05 mm. How wide is the slit?

Homework Equations


a=width of slit
y=distance from central max to specific spot
L=distance of screen from the slit
λ=wavelength of light
sinΘ≈Θ=y/L
minima occurs at: a*sinΘ=mλ
(found on internet) approximation of maxima occurs at: a*sinΘ=(m+.5)λ

The Attempt at a Solution


L=2m
λ=650*10^-9m
each maxima is the same distance from the central maxima so if the distance between the 2 first order maxima is .00205m then
y=.001025m

a*(.001025/2)=(1.5)(650*10^-9)
I found answer to be 0.001902m (wrong)

just in case I decided to try and see using the minima formula a*(.001025/2)=(650*10^-9)
answer :0.001268m (wrong)

any assistance would be great.
 
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The maximum of the sinc function is not at m+0.5 . It's close, but not exactly.
 
Khashishi said:
The maximum of the sinc function is not at m+0.5 . It's close, but not exactly.
what equation should I use then?
 
You differentiate the intensity expression...
 

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