Find x in radians using [0,2pi] | Sin(3x)= -0.1658 | Step-by-Step Solution"

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Homework Help Overview

The problem involves finding the values of x in radians within the interval [0, 2π] for the equation sin(3x) = -0.1658. The context is trigonometric equations and their solutions on the unit circle.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the original poster's approach to solving the equation and question the validity of the initial answer. There is a suggestion that multiple solutions exist, prompting further exploration of the unit circle and sine function properties.

Discussion Status

Some participants have provided hints and guidance regarding the properties of the sine function and the implications of the negative value. There is an ongoing exploration of how many solutions exist and how to find them within the specified range.

Contextual Notes

There is uncertainty regarding the completeness of the original poster's work, as they express confusion about the number of solutions and the domain constraints. The discussion highlights the need to consider the unit circle for finding valid angles.

darshanpatel
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Homework Statement



Find x in radians using [0,2pi]

Sin(3x)= -0.1658

Homework Equations



-None-

The Attempt at a Solution



3x=Sin-1(-0.1658)

x=sin-1(-0.1658)/3

x= -0.055523061

The teacher gave me a whole page to do the problem, so I don't know if there should be more work or not. Not positive if this answer is correct also.
 
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I believe that there should be 6 answers to this equation.
 
Ok, could you help me get them? I don't understand this question at all.
 
Your work was all right, and your answer is in fact a zero of the equation. But it doesn't lie in the domain you are looking for.

When solving these equations, think of the unit circle.
sin and the height of the circle are related. So solving for when the sin(x) = -.1658, can you see how many solutions are?
 
darshanpatel said:
Ok, could you help me get them? I don't understand this question at all.

Here are some hints:

sin (pi - θ) = sinθ
sin(2n*pi-θ)=-sinθ
plus other similar relations

chet
 
I still don't understand. If I could get the answers, I could try back-tracking to get the work and understand how to do it.
 
You need to think logically about your answer; it's not in the range 0 to 2pi. You have a negative angle that has this sine. What positive angles in the range 0 to 2pi will have that sine?
 

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